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Cuda dim3 example
Cuda dim3 example








  1. CUDA DIM3 EXAMPLE SOFTWARE
  2. CUDA DIM3 EXAMPLE CODE

In particular, when the total threads in the x-dimension ( gridDim.x*blockDim.x) is less than the size of the array I wish to process, then it's common practice to create a loop and have the grid of threads move through the entire array. In the CUDA documentation, these variables are defined here It's common practice when handling 1-D data to only create 1-D blocks and grids. blockDim.x * gridDim.x gives the number of threads in a grid (in the x direction, in this case)īlock and grid variables can be 1, 2, or 3 dimensional.gridDim.x,y,z gives the number of blocks in a grid, in the.blockDim.x,y,z gives the number of threads in a block, in the.Let us look into couple of scenarios and how global index is calculated in each case. The global index will help us access individual thread among millions of threads that are dispatched to the GPU. With the help of these four variables, we can calculate unique global index of each thread. Refers to the maximum number of blocks in a grid in all the dimension and it starts from 1.All thread blocks have the same dimension.Refers to the maximum number of threads in a block in all the dimension and it starts from 1.Refers to the block ID in a grid and it starts from 0.

cuda dim3 example

  • It is a dim3 variable and each dimension can be accessed by blockIdx.x, blockIdx.y, blockIdx.z.
  • cuda dim3 example

    So, if number of threads in X dim in a block is 32, then threadIdx.x ranges from 0 to 31 in each block.

  • Refers to the thread ID with in a block and it starts from 0.
  • cuda dim3 example

  • It is a dim3 variable and each dimension can be accessed by threadIdx.x, threadIdx.y, threadIdx.z.
  • Implicit variables initialised by CUDA runtime If the above boundary conditions are not met, then the kernel will not be launched. int devNo = 0 cudaDeviceProp iProp cudaGetDeviceProperties(&iProp, devNo) printf("Maximum grid size is: (") for (int i = 0 i < 3 i++) printf("%d\t", iProp.maxGridSize) printf(")\n") printf("Maximum block dim is: (") for (int i = 0 i < 3 i++) printf("%d\t", iProp.maxThreadsDim) printf(")\n") printf("Max threads per block: %d\n", iProp.maxThreadsPerBlock) We can get these values with the following lines of code. My machine has NVIDIA GeForce GTX 1650 card whose device architecture is Turing and the following are the boundary values.īlock boundary value - (1024, 1024, 1024) and the product of all the 3 dim should be less than or equal to 1024. The block and grid variables do have boundary values and the boundary values depend on the GPU device architecture. int nx //total threads in X dimension int ny //total threads in Y dimension int nz //total threads in Z dimension nx = 128 //128 threads in X dim ny = nz = 1 //1 thread in Y & Z dim //32 threads in X and 1 each in Y & Z in a block dim3 block(32,1,1) //4 blocks in X & 1 each in Y & Z dim3 grid(nx/block.x, ny/block.y, nz/block.z) cuda_kernel >()

    cuda dim3 example

    CUDA DIM3 EXAMPLE SOFTWARE

    From a software perspective the block and grid variables are three dimensional. For sake of simplicity we can name total number of threads in a block as block and total number of blocks in a grid as grid. Total number of threads in all the blocks remain the same.

    CUDA DIM3 EXAMPLE CODE

    Thus in the above code total number of threads in a block is 1 and there is 1 such block in a grid. The first parameter indicates the total number of blocks in a grid and the second parameter indicates the total number of threads in a block. In the above code, to launch the CUDA kernel two 1's are initialised between the angle brackets. Pre-processor directives #include #include "cuda_runtime.h" #include "device_launch_parameters.h" //Device code _global_ void cuda_kernel() I’ll consider the same Hello World! code considered in the previous article. In order to launch a CUDA kernel we need to specify the block dimension and the grid dimension from the host code.










    Cuda dim3 example